The reagent one would choose to transform `CH_(3)CH_(2)COCl` into `CH_(3)CH_(2)COCH_(3)` is _______.

Options

A. `CH_(3)Mgl`
B. `(CH_(3))_(2)Cd`
C. `(CH_(3)O)_(2)Mg`
D. `CH_(3)Cl`

Answer

To transform `CH3CH2COCl` (an acid chloride) into `CH3CH2COCH3` (a ketone), we can follow these steps:

### Step 1: Identify the Reaction
We need to convert an acid chloride to a ketone. The general reaction involves the addition of a nucleophile to the carbonyl carbon of the acid chloride.

### Step 2: Choose the Nucleophile
The nucleophile we will use is an organocadmium reagent, specifically `CH3CdR` (where R is another alkyl group). In this case, we can use `CH3Cd(CH3)` which is an organocadmium reagent.

### Step 3: Mechanism of Reaction
1. The nucleophile (`CH3-` from the organocadmium reagent) will attack the carbonyl carbon of the acid chloride (`CH3CH2COCl`).
2. This results in the formation of a tetrahedral intermediate.
3. The chlorine atom (a good leaving group) will leave, resulting in the formation of the ketone `CH3CH2COCH3`.

### Step 4: Final Product
After the reaction, we will have `CH3CH2COCH3`, which is the desired ketone.

### Conclusion
The reagent that we would choose to transform `CH3CH2COCl` into `CH3CH2COCH3` is `CH3Cd(CH3)` (organocadmium reagent).

### Answer
The reagent one would choose to transform `CH3CH2COCl` into `CH3CH2COCH3` is **organocadmium reagent**.

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