Methyl cyanide on reduction with `H_2`/Ni gives ___________.

Options

A. methylamine
B. ethylamine
C. propylamine
D. dimethylamine

Answer

To solve the question, "Methyl cyanide on reduction with H2/Ni gives __________," we will follow these steps:

### Step-by-Step Solution:

1. **Identify Methyl Cyanide**:
Methyl cyanide, also known as acetonitrile, has the chemical formula CH₃CN. It contains a methyl group (CH₃) attached to a cyanide group (CN).

2. **Understand the Reduction Process**:
The reduction of methyl cyanide involves the addition of hydrogen (H₂) in the presence of a nickel catalyst (Ni). This process typically involves the breaking of the triple bond between carbon and nitrogen in the cyanide group.

3. **First Stage of Reduction**:
When methyl cyanide is subjected to reduction, the triple bond (C≡N) is first reduced to a double bond (C=N). This results in the formation of an intermediate compound, which is an imine (specifically, methyl imine, CH₃=NH).

4. **Second Stage of Reduction**:
Continuing the reduction process with another equivalent of hydrogen (H₂) in the presence of nickel will further reduce the imine (C=N) to an amine (C-NH₂).

5. **Final Product**:
The final product after full reduction of methyl cyanide is ethylamine (C₂H₅NH₂). This is because the methyl group (CH₃) from methyl cyanide becomes part of the ethylamine structure.

### Conclusion:
Thus, methyl cyanide on reduction with H₂/Ni gives ethylamine (C₂H₅NH₂).

### Answer:
Ethylamine

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