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n-Propyl bromide (A) when boiled with aq...

n-Propyl bromide (A) when boiled with aqueous KOH undergoes hydrolysis forming compound 'B' . The compound 'B' reacts with concentrated sulphuric acid at 443 K to yields compound 'C'. Identify the compound 'B' and 'C'.

A

`CH_(3)-CH=CH_(2), CH_(3)-C=CH `

B

`CH_(3)-underset(CH_(3))underset(|)CH-OH , CH_(3)-CH=CH_(2)`

C

`CH_(3)-CH_(2)-CH_(2)-OH , CH_(3)-CH=CH_(2)`

D

`CH_(3)-underset(OH)underset(|)CH-CH_(2)-Br, CH_(3)-CH=CH-Br`

Text Solution

Verified by Experts

The correct Answer is:
C
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