The angular speed of the electron in the first orbit in a H atom is `4.103 xx 10^(16)` rad/s. Hence the angular speed of the electron in the third orbit is

Options

A. `1.52 xx 10^(15)` rad/s
B. `1.25 xx 10^(15)` rad/s
C. `1.52 xx 10^(14)` rad/s
D. `1.25 xx 10^(14)` rad/s

Answer

A

Explanation

`omega_(n)=omega_(1)/n^(3)`
`:. omega_(3)=omega_(1)/27=(4.103xx10^(16))/27`
`=1.52xx10^(15)` rad/sec.