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Energy of the lowest level of H-atom is ...

Energy of the lowest level of H-atom is -13.6 eV. The energy of the emitted photons in transition from fourth to second energy state is

A

2.55 eV

B

3.2 eV

C

4.5 eV

D

5.4 eV

Text Solution

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The correct Answer is:
A
`E_(4)=E_(1)/16=(-13.6)/16=-0.85 eV`
`E_(2)=E_(1)/4=(-13.6)/4=-3.4 eV`
`:. E_(4)-E_(2)=-0.85+3.4=2.55 eV`
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