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the nergy of an excited state of H atom ...

the nergy of an excited state of H atom is -0.85 eV. What will be the quantum number of the orbit, if the ground state energy for hydrogen is -13.6 eV?

A

4

B

3

C

2

D

1

Text Solution

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The correct Answer is:
A
`E_(n)=E_(1)/n^(2)" ":. n^(2)=E_(1)/E_(n)=(-13.6)/(-0.85)=16`
`:. n=4`
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