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The ionisation potential of H-atom is 13...

The ionisation potential of H-atom is 13.6 eV. The energy required to remove an electron from the second orbit of hydrogen is

A

27.2 eV

B

13.6 eV

C

6.8 eV

D

3.4 eV

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(n)=E_(1)/n^(2)" ":. E_(2)=E_(1)/4=13.6/4=3.4 eV`
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