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If the ionisation potential of a H-atom ...

If the ionisation potential of a H-atom is `omega`, then its energy in the first excited state is

A

`omega/2`

B

`omega/3`

C

`omega/4`

D

`omega/5`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(n)=E_(1)/n^(2)`
Thus energy in the first excited state is,
`E_(2)=E_(1)/4=omega/4`
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