If the frequency of revolution of electron in an orbit H atom is n then the equivalent current is

Options

A. `(2pi r e)/n`
B. `(en)/(2pi r)`
C. `e^(2) pi n`
D. en

Explanation

To find the equivalent current when the frequency of revolution of an electron in an orbit of a hydrogen atom is \( n \), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Current**:
Current (\( I \)) is defined as the charge (\( Q \)) that flows per unit time (\( t \)). Mathematically, it can be expressed as:
\[ I = \frac{Q}{t} \]

2. **Identify the Charge of the Electron**:
The charge of an electron (\( e \)) is approximately \( 1.6 \times 10^{-19} \) coulombs.

3. **Relate Frequency to Time**:
The frequency (\( n \)) of revolution indicates how many times the electron completes a full orbit in one second. Therefore, the time period (\( T \)) for one complete revolution is the reciprocal of frequency:
\[ T = \frac{1}{n} \]

4. **Calculate the Current**:
Since the electron completes \( n \) revolutions in one second, the total charge that passes through a point in one second is the charge of the electron multiplied by the frequency:
\[ I = Q \times n = e \times n \]

5. **Substitute the Charge of the Electron**:
Now, substituting the value of \( Q \) (which is \( e \)):
\[ I = e \cdot n \]

6. **Conclusion**:
Thus, the equivalent current when the frequency of revolution of the electron in the orbit of a hydrogen atom is \( n \) is:
\[ I = e \cdot n \]

### Final Answer:
The equivalent current is \( e \cdot n \).