If R is the Rydberg's constant, the energy of an electron in the ground state H atom is

Options

A. `(Rc)/h`
B. `(-1)/(Rhc)`
C. `-Rhc`
D. `(vc)/R`

Answer

C

Explanation

`E_(n)=(-me^(4))/(8 in_(0)^(2)n^(2)h^(2))`
`E_(1)=(-me^(4))/(8in_(0)^(2) h^(2))`
Multiplying and dividing above `eq^(n)` by hc
`:. E_(1)=(-me^(4))/(8 in_(0)^(2)h^(2))(hc)/(hc)=(-me^(4))/(8 in_(0)^(2)h^(3)) hc`
`:. E_(1)=-Rhc" ":' R=(me^(4))/(8c in_(0)^(2)h^(3))`