According to bohr's theory, the wave number of last line of balmer series is `(R =1.1xx10^(7)m^(-1))`

Options

A. `5.5xx10^(5) m^(-1)`
B. `4.4xx10^(7) m^(-1)`
C. `2.75xx10^(6) m^(-1)`
D. `2.75xx10^(8) m^(-1)`

Answer

C

Explanation

For last line of Balmer series,
`p=2` and `n=oo`
`bar(lambda)=R(1/p^(2)-1/n^(2))=1.1xx10^(7) (1/4-1/oo)`
`=2.75xx10^(6) m^(-1)`