According to the Bohr's theory the wave length of shortest wavelength of a spectral line in Barckett series is

Options

A. 4480 Å
B. 8800 Å
C. 14545 Å
D. 18450 Å

Answer

C

Explanation

For shortest wavelength of Balmer series,
`p=2` and `n=oo`
`bar(lambda)=1/lambda=R(1/p^(2)-1/n^(2))=R(1/4-1/oo)`
`=(1.1xx10^(7))/4`
`=2.75xx10^(6) m^(-1)`