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The seond line of Balmer series has wave...

The seond line of Balmer series has wavelength `4861 Å` The wavelength o fthe first line Balmer series is

A

6563 Å

B

3656 Å

C

6380 Å

D

3860 Å

Text Solution

Verified by Experts

The correct Answer is:
A
For `H_(beta)` line of Balmer series,
`p=2` and `n=4`
`:. 1/lambda_(beta)=R (1/p^(2)-1/n^(2))=R(1/4-1/16)`
`:. lambda_(beta)=64/(12R)`
For `H_(alpha)` line of Balmer series,
`p=2` and `n=3`
`:. 1/lambda_(alpha)=R (1/p^(2)-1/n^(2))=R(1/4-1/9)`
`:. lambda_(alpha)=36/(5R)` ...(2)
Dividing eq. (2) by eq. (1) we have,
`lambda_(alpha)=(36xx12xxlambda_(beta))/(5xx64)=(36xx12xx4861)/(5xx64)`
`=6563 Å`
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