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When the radioactive isotope .(88)Ra^(22...

When the radioactive isotope `._(88)Ra^(228)` decays in series by the emission of `3 alpha` and `1 beta` particle, the isotope finally formed is

A

`._(89)X^(229)`

B

`._(86)X^(222)`

C

`._(83)X^(216)`

D

`._(83)X^(215)`

Text Solution

Verified by Experts

The correct Answer is:
C
`._(88)Ra^(228) overset(3alpha)(rarr) ._(82)Y^(216) overset(1 beta)(rarr) ._(83)Y^(216)`
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