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An electron and a proton are accelerated...

An electron and a proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths will be

A

`(m_(p)/m_(e))^(1//2)`

B

`m_(e)/m_(p)`

C

`m_(p)/m_(e)`

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda =h/sqrt(2 mq V)`
`lambda prop 1/sqrt(m)`
`lambda_(e)/lambda_(p)=sqrt(m_(p)/m_(e))`
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