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If the kinetic energy of a free electron...

If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factor

A

2

B

`1//2`

C

`sqrt(2)`

D

`1//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda=h/sqrt(2 m qV)`
`lambda prop 1/sqrt(E_(k))`
`lambda_(1)/lambda_(2)=sqrt(E_(K_(2))/(E_(K_(1))))=sqrt(2)/1`
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