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The de-Broglie wavelength associated wit...

The de-Broglie wavelength associated with electrons revolving round the nucleus in a hydrogen atom in the ground state will be

A

3.3 Å

B

1.3 Å

C

6.6 Å

D

20 Å

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To find the de-Broglie wavelength associated with electrons revolving around the nucleus in a hydrogen atom in the ground state, we can follow these steps: ### Step 1: Understand the de-Broglie wavelength formula The de-Broglie wavelength (λ) of a particle is given by the formula: \[ \lambda = \frac{h}{mv} \] where: - \( h \) is the Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)), - \( m \) is the mass of the electron (\(9.11 \times 10^{-31} \, \text{kg}\)), - \( v \) is the velocity of the electron. ### Step 2: Use Bohr's model for the hydrogen atom According to Bohr's model, the angular momentum of an electron in an orbit is quantized and given by: \[ mvr = n \frac{h}{2\pi} \] For the ground state of hydrogen, \( n = 1 \). Thus, we have: \[ mvr = \frac{h}{2\pi} \] ### Step 3: Rearrange the equation to find velocity From the angular momentum equation, we can express the velocity \( v \) as: \[ v = \frac{h}{2\pi mr} \] ### Step 4: Determine the radius of the electron's orbit The radius of the electron's orbit in the ground state (n=1) for hydrogen is given by: \[ r = 0.529 \, \text{Å} = 0.529 \times 10^{-10} \, \text{m} \] ### Step 5: Substitute the radius into the velocity equation Now substituting the value of \( r \) into the velocity equation: \[ v = \frac{h}{2\pi m (0.529 \times 10^{-10})} \] ### Step 6: Substitute \( v \) into the de-Broglie wavelength formula Now we can substitute \( v \) back into the de-Broglie wavelength formula: \[ \lambda = \frac{h}{m \left(\frac{h}{2\pi m (0.529 \times 10^{-10})}\right)} \] ### Step 7: Simplify the expression This simplifies to: \[ \lambda = 2\pi (0.529 \times 10^{-10}) = 3.3 \times 10^{-10} \, \text{m} = 3.3 \, \text{Å} \] ### Final Answer Thus, the de-Broglie wavelength associated with the electron in the ground state of a hydrogen atom is: \[ \lambda = 3.3 \, \text{Å} \]

To find the de-Broglie wavelength associated with electrons revolving around the nucleus in a hydrogen atom in the ground state, we can follow these steps: ### Step 1: Understand the de-Broglie wavelength formula The de-Broglie wavelength (λ) of a particle is given by the formula: \[ \lambda = \frac{h}{mv} \] where: ...
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