The angular speed of the electron in the first orbit in a hydrogen atom is

Options

A. `5.1 xx10^(16)` rad/s
B. `1.4xx10^(16)` rad/s
C. `4.1xx10^(16)` rad/s
D. `1.1xx10^(16)` rad/s

Answer

C

Explanation

`omega_(n)=(pi me^(4))/(2 epsi_(0)^(2) n^(3) h^(3))`
`:. omega_(1)=(3.14xx9.1xx10^(-31)xx(1.6xx10^(-19))^(4))/(2xx(8.85xx10^(-12))^(2)xx1xx(6.63xx10^(-34))^(3))`
`=4.1xx10^(16)` rad/s