The radius of the first Bohr orbit of the hydrogen atom is 0.53 Å and angular momentum of the electron in that orbit is `1.055xx10^(-34)` Js. The linear speed of the electron in the second orbit of the H-atom is

Options

A. `1.1xx10^(6)` m/s
B. `1.1xx10^(-6)` m/s
C. `2.1 xx10^(6)` m/s
D. `2.1 xx10^(-6)` m/s

Answer

A

Explanation

`L_(1)= mr_(1) v_(1)`
`:. v_(1)=L_(1)/(mr_(1))=(1.055xx10^(-34))/(9.1xx10^(-31)xx0.53xx10^(-10))`
`v_(2)=v_(1)/2`
`=(2.181xx10^(6))/2`
`=1.1xx10^(6)` m/s