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Energy of an electron in second Bohr orb...

Energy of an electron in second Bohr orbit of H-atom is -3.4 eV. The Rydbergs constant is

A

`2.1 xx10^(-7) m^(-1)`

B

`1.1xx10^(7) m^(-1)`

C

`2.1xx10^(7) m^(-1)`

D

`1.1xx10^(-7) m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(n)=E_(1)/n`
`E_(2)=E_(1)/4`
`E_(1)=4 E_(1)=-Rhc`
`:. R=(4xx3.4xx1.6xx10^(-19))/(6.63xx10^(-34)xx3xx10^(8))=1.1xx10^(7) m^(-1)`
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