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The percentage increase in the rest mass...

The percentage increase in the rest mass of an electron when it is moving at a speed of 0.6 c where c is the speed of light, is

A

0.52

B

0.75

C

0.25

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
C

`m=m_(0)/sqrt(1-v^(2)/c^(2))=m_(0)/sqrt(1-((0.6 c)/c)^(2))`
`=m_(0)/sqrt(1-0.36)=m_(0)/sqrt(0.64)=m_(0)/0.8`
`m=1.25 m_(0)`
% increase in mass `=((m-m_(0))/m_(0))xx100`
`=((1-25 m_(0)-m_(0))/m_(0))xx100`
`=25 %`
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