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The ratio of the radii of the nuclei .(1...

The ratio of the radii of the nuclei `._(13)A^(27)` and `._(52)Te^(125)` is approximately

A

`6 : 10`

B

`27 : 125`

C

`13 : 52`

D

`14 : 73`

Text Solution

Verified by Experts

The correct Answer is:
A
`R prop A^(1/3)`
`R_(1)/R_(2)=(A_(1)/A_(2))^(1/3)`
`=(27/125)^(1/3)=[(3/5)^(3)]^(1/3)`
`=3/5=6/10`
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