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The energy of electron in an excited hyd...

The energy of electron in an excited hydrogen atom is `-3.4eV`. Its angular momentum according to bohr's theory will be

A

`2.11xx10^(-34)` Js

B

`2.11xx10^(+34)` Js

C

`2.11xx10^(-34)` erg s

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
The electron is in the second orbit `(n=2)`
Hence `L=(nh)/(2 pi)=(2 h)/(2 pi) =h/pi`
`=(6.63xx10^(-34))/3.14`
`=2.11xx10^(-34) J.s.`
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