An electron has a mass of `9.1 xx 10^(-31)kg`. It revolves round the nucleus in a circular orbit of radius `0.529 xx 10^(-10)` metre at a speed of `2.2 xx 10^(6) m//s`. The magnitude of its linear momentum in this motion is

Options

A. `1.1xx10^(-34): kg ms"^(-1)`
B. `2.0xx10^(-24)" kg ms"^(-1)`
C. `4.0xx10^(-24)" kg ms"^(-1)`
D. `4.0xx10^(-31)" kg ms"^(-1)`

Answer

B

Explanation

`p=mv`
`p_(1)=m_(1)v_(1)`
`p_(1)=9.1xx10^(-31) xx2.2xx10^(6)`
`=2xx10^(-24)` kgm/s