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The radius of the nucleus .(8)O^(16) is ...

The radius of the nucleus `._(8)O^(16)` is `3xx10^(-15)m`. The density of this nucleus will be

A

`2.35xx10^(-17)" kg m"^(-3)`

B

`3.35xx10^(17)" kg m"^(-3)`

C

`2.35xx10^(17)" kg m"^(-3)`

D

`3.35xx10^(-17)" kg m"^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`rho=m/V=m/(4/3 pi r^(3))=(3m)/(4pi r^(3))`
`=(3xx16xx1.67xx10^(-27))/(4xx3.14xx(3xx10^(-15))^(3))`
`=2.35xx10^(17)" kg/m"^(3)`
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