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The ionization potential of a hydrogen a...

The ionization potential of a hydrogen atom is 13.6 eV. What will be the energy of the atom corresponding to n=2?

A

`-6.8 eV`

B

`-3.4 eV`

C

`-27.2 eV`

D

`-4.4 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
Ionisation potential is the energy required to remove the electron from the first orbit.
`:. E_(1)=-13.6` eV
`E_(2) = ?`
`E_(2)=E_(1)/4 =(-13.6)/4=-3.4 eV`
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