`lambda_(a)//lambda_(beta)` in Balmer series is

Options

A. `27 : 20`
B. `20 : 27`
C. `5 : 36`
D. `12 : 64`

Answer

A

Explanation

For `lambda_(alpha)` in Balmer series `p=2` and `n=3`
`:. 1/lambda =R [1/p^(2) -1/n^(2)]`
`:. 1/lambda_(1)= R[1/4-1/9]`
`lambda_(1)=36/(5R)` ...(1)
For `lambda_(B)` in Balmer series `p=2` and `n=4`
`:. 1/lambda_(2)=R[1/4 -1/16]`
`lambda_(2)=64/(12 R)` ...(2)
`lambda_(1)/lambda_(2)=36/(5R)xx(12 R)/64`
`=(36xx12)/(5xx64)`
`=27/20`