The de Broglie wavelenth of `1 mg` grain of sand blown by a `20 m s^-1` wind is :

Options

A. `33.15xx10^(-36)m`
B. `33.15xx10^(-33) m`
C. `33.15xx10^(-30) m`
D. `33.15xx10^(30) m`

Answer

C

Explanation

`lambda =h/(mv) =(6.63xx10^(-34))/(1xx10^(-3)xx10^(-3) xx20)`
`=3.315xx10^(-29) m`