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In hydrogen atom, the electron is making...

In hydrogen atom, the electron is making `6.6xx10^(15) rev//sec` around the nucleus in an orbit of radius `0.528 A`. The magnetic moment `(A-m^(2)) will be

A

`1xx10^(-15) Am^(2)`

B

`1xx10^(-10) Am^(2)`

C

`1xx10^(-23) Am^(2)`

D

`1xx10^(-27) Am^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`M=I A`
`=q f pi r^(2)`
`=1.6xx10^(-19) xx6.6xx10^(15)xx3.14xx(5.28xx10^(-11))^(2)`
`=1 xx10^(-23) A m^(2)`
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