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The radius of hydrogen atom in its groun...

The radius of hydrogen atom in its ground state is `5.3 xx 10^(-11)m`. After collision with an electron it is found to have a radius of `21.2 xx 10^(-11)m`. What is the principle quantum number of `n` of the final state of the atom ?

A

`n=4`

B

`n=3`

C

`n=2`

D

`n=16`

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(n)=r_(1)n^(2)`
`:. n^(2)=r_(n)/r_(1)=(21.2xx10^(-11))/(5.3xx10^(-11))=4`
`:. n=2`
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