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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is

A

`pi r^(2)`

B

`2 pi r`

C

`pi r`

D

`sqrt(2) pi r`

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda=h/(mv)`
`lambda=(hr)/(mvr)=(hr)/((nh)/(2pi))`
`n lambda=2 pi r" "(n=1)`
`:. lambda =2 pi r`
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