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In the given circuit, when the galvanome...

In the given circuit, when the galvanometer G shows no deflection, the current in the `5 Omega` resistance is ,

A

0.4A

B

0.6A

C

0.8A

D

1.0A

Text Solution

Verified by Experts

The correct Answer is:
A
`(R_(ABC))/(R_(ADC))=(12)/(30)=(2)/(5)`
`therefore` Current will be divided in the ratio of 5 : 2.
Current through ABC = 1A
Current through ADC =0.4A
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