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A cell of e.m.f. of 1.08 V is balanced b...

A cell of e.m.f. of 1.08 V is balanced by a 216 cm length of a potentiometer. What is the length of the wire that would balance a cell of e.m.f. 1.5 V ?

A

250 cm

B

290 cm

C

300 cm

D

310 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`(E_(1))/(E_(2))=(l_(1))/(l_(2)) therefore (1.08)/(1.5)=(216)/(l_(2))`
`therefore l_(2)=(216xx1.5)/(1.08)=300 cm`
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