As is the cross sectional area and `rho` is the specific resistance of a potentiometer wire. If I is the current passing through the potentiometer wire, then the potential gradient along the length of the wire is given by

Options

A. `(I A)/(rho)`
B. `I A rho`
C. `(I rho)/(A)`
D. `(I)/(rho A)`

Answer

C

Explanation

By Ohm's law, `P.D.= V=IR =(Irho L)/(A)`
`therefore " Potential gradient " =(V)/(L)=(I rho)/(A)`