Molarity of 0.2 N `H_(2) SO_(4)` is

Options

A. `0.2`
B. `0.4`
C. `0.6`
D. `0.1`

Explanation

To find the molarity of a 0.2 N solution of sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Understand the relationship between Normality and Molarity
Normality (N) is related to molarity (M) by the equation:
\[ \text{Normality} = \text{Molarity} \times \text{N factor} \]

### Step 2: Determine the N factor for H₂SO₄
The N factor for an acid is equal to the number of H⁺ ions it can donate. For sulfuric acid (H₂SO₄):
- When H₂SO₄ dissolves in water, it dissociates to produce 2 H⁺ ions and 1 SO₄²⁻ ion.
- Therefore, the N factor for H₂SO₄ is 2.

### Step 3: Use the Normality to find Molarity
Given that the normality of the solution is 0.2 N, we can substitute the values into the relationship:
\[ 0.2 = \text{Molarity} \times 2 \]

### Step 4: Solve for Molarity
Rearranging the equation to solve for molarity:
\[ \text{Molarity} = \frac{0.2}{2} = 0.1 \, M \]

### Conclusion
The molarity of the 0.2 N H₂SO₄ solution is 0.1 M.

---