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When 6 gm urea dissolve in 180 gm H(2)O....

When `6` gm urea dissolve in `180` gm `H_(2)O`. The mole fraction of urea is [Mol. Wt. of urea = `60`]

A

`( 10 )/( 10.1)`

B

`( 10.1 )/( 10)`

C

`(10.1)/(0.1)`

D

`(0.1)/(10.1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`n_(urea)= ( 6)/(60) =0.1 ` `n_(H_(2)O)= ( 180)/(18) =10`
`X_("urea")= (n_(urea))/(n_(urea)+n_(H_(2)O)`
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