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A solution is prepared from A,B,C and D....

A solution is prepared from A,B,C and D.Mole fraction of A,B and C are 0.1, 0.2 and 0.4 respectively then, mole fraction of D is

A

`0.2`

B

`0.1`

C

`0.3`

D

`0.4`

Text Solution

Verified by Experts

The correct Answer is:
C
Mole fraction of `A+B+C+D =1 `
`0.1 + 0.2 + 0.4 + D = 1 `
Mole fraction of D `=1- 0.7 = 0. 3 `
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