The rise in boiling point of a solution containing `1.8g` glucose in `100g` of a solvent is `0.1^(@)C`. The molal elevation constant of the liquid is-

Options

A. `0.01 K //m`
B. `0.1 K //m`
C. `1 K //m`
D. `10 K //m`

Answer

C

Explanation

18gms of glucose in 1 kg. of solvent. Molecular wt. of glucose is 180. Hence molality of glucose is 0.1 .
`Delta T_(B) = K_(b) m `
`0.1 =K_(b)