`0.15`g of a subatance dissolved in `15`g of solvent boiled at a temperature higher at `0.216^(@)`than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is `2.16^(@)C`

Options

A. 1.01
B. 10
C. 10.1
D. 100

Answer

D

Explanation

`M_(B) = (W_(B) xx K_(b) xx 1000)/( W_(A) xxDelta T_(b))`
`= ( 0.15 xx 2.16 xx 1000)/( 15 xx 0.216) = 100`