The freezing point of a 0.05 molal solution of a non-electrolyte in water is `[K_(f)=1.86^(@)C//m]`

Options

A. `- 1.86 ^(@)C `
B. `- 9.3 ^(@)C `
C. ` -0.093^(@)C `
D. ` - 0.93^(@)C `

Answer

C

Explanation

`Delta T_(f) =K_(f) . m = 1.86 xx 0.05 = 0.093^(@)C`
F.P. of solution = F.P. of water `=Delta T_(f)`