In equimolar solution of glucose, NaCl and `BaCl_(2)` , the order of osmotic pressure at same temperature is as follow `:`

Options

A. Glucose `gt ` NaCl `gt BaCl_(2)`
B. NaCl` gtBaCl_(2) gt ` Glucose
C. `BaCl_(2) gt ` NaCl `gt` Glucose
D. Glucose `gt BaCl_(2) gt ` NaCl

Answer

C

Explanation

Glucose `rarr ` does not ionise ( one particle )
`NaCl rarr Na^(+ ) +Cl^(-)` ( two particles )
`BaCl_(2) rarr Ba^(++) + 2Cl^(-) `( three particles )
Osmotic Pressure` prop` Number of particles in the solution.