The molality of 90% (w/v)`H_(2)SO_(4)` solution is [density = 1.8 gm`//`ml ]

Options

A. 0.102
B. 1.02
C. 10.2
D. 102

Answer

C

Explanation

Molecular wt. of `H_(2)SO_(4) = 98`
90% `H_(2)SO_(4)` solution means 900 gm `H_(2)SO_(4)` dissolved in 1000mL of solution.
Mass of solution `= 1000 xx1.8 = 1800 g `
`:.` Mass of water `= 1000 - 100 =900 g `
Molality `= ( 900) /(98) xx ( 1000)/(900) =10.2 `