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A solution contains 25% H(2)O, 25% C(2)H...

A solution contains 25% `H_(2)O`, 25% `C_(2)H_(5)OH ` and 50% `CH_(3)COOH` by mass.The mole fraction of `H_(2)O `would be

A

0.25

B

2.5

C

0.503

D

5.03

Text Solution

Verified by Experts

The correct Answer is:
C
`n_(H_(2)O) =( 25)/( 18) , n_(C_(2)H_(5)OH) = ( 25)/( 46) ~~0.54`
`n_(CH_(3)COOH) = ( 50)/( 60) ~~0.83`
`X_(H_(2)O ) = ( n_(H_(2)O) )/(n_(H_(2)O) + n_(C_(2)H_(5)OH) + n_(CH_(3)COOH))~~( 1.4 )/( 2.8)`
`~~ 0.5 `
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