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If y=sqrt(cos2x)," then: "yy(2)+2y^(2)=...

If `y=sqrt(cos2x)," then: "yy_(2)+2y^(2)=`

A

0

B

`-y^(2)=`

C

`y_(1)^(2)`

D

`yy_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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