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If y=log(logx)," then "xy(2)+x(y(1))^(2)...

If `y=log(logx)," then "xy_(2)+x(y_(1))^(2)=`

A

y

B

`-y`

C

`-y_(1)`

D

`y_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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