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If y=e^(1+logx)," then: "(dy)/(dx)...

If `y=e^(1+logx)," then: "(dy)/(dx)`

A

e

B

1

C

0

D

`logx*e^(logex)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If y=e^(1+xy)," then "(dy)/(dx)=

    A
    `(y^(2))/(1+xy)`
    B
    `(y^(2))/(1-xy)`
    C
    `(-y^(2))/(1+xy)`
    D
    `(y^(2))/(xy-1)`
  • If y = e^(1//x) " then " (dy)/(dx) = ?

    A
    `(1)/(x).e^((1//x-1))`
    B
    `(-e^(1//x))/(x^(2))`
    C
    `e^(1//x) log x`
    D
    none of these
  • If y=x^(logx) ,then (dy)/(dx)=

    A
    ` 2x ^((logx-1)) logx `
    B
    ` x^((logx-1))`
    C
    ` (2)/( xlogx )`
    D
    ` x^((logx-1))logx `
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