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If y=log[(x-1)^(1//2)-(x+1)^(1//2)]," th...

If `y=log[(x-1)^(1//2)-(x+1)^(1//2)]," then: "(dy)/(dx)=`

A

`(1)/(2)(x^(2)-1)^(-1//2)`

B

`-(1)/(2)(x^(2)-1)^(-1//2)`

C

`(1)/(2)(x^(2)-1)^(1//2)`

D

`(1)/(2)(1-x^(2))^(-1//2)`

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