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When SO2 is passed through acidified K2C...

When `SO_2` is passed through acidified `K_2Cr_2O_7` solution

A

The solution turns blue

B

The solution is decolourised

C

`SO_(2)` is reduced

D

Green `Cr_(2)(SO_(4))_(3)` is formed

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4) +3SO_(2) to K_(2)SO_(4) +underset("Green")(Cr_(2)(SO_(4))_(3)) +3H_(2)O`
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