Which of the following will not occur

Options

A. `Fe+ H_(2)SO_(4) to FeSO_(4) + H_(2)`
B. `Cu+ 2AgNO_(3) to Cu(NO_(3))_(2) + 2Ag`
C. `2KBr+ I_(2) to 2KI + Br_(2)`
D. `CuO + H_(2) to Cu+ H_(2)O`

Explanation

To determine which of the given reactions will not occur, we need to analyze each option based on the principles of the electrochemical series and the reactivity of the elements involved. Let's break down the analysis step by step.

### Step 1: Analyze the first reaction - Fe + H2SO4
- **Reaction**: Fe + H2SO4 → FeSO4 + H2
- **Analysis**: Iron (Fe) is above hydrogen (H) in the electrochemical series, meaning it can displace hydrogen from sulfuric acid. Therefore, this reaction **can occur**.

### Step 2: Analyze the second reaction - Cu + AgNO3
- **Reaction**: Cu + AgNO3 → Cu(NO3)2 + Ag
- **Analysis**: Copper (Cu) is above silver (Ag) in the electrochemical series, indicating that copper can displace silver from silver nitrate. Thus, this reaction **can occur**.

### Step 3: Analyze the third reaction - KBr + I2
- **Reaction**: KBr + I2 → KI + Br2
- **Analysis**: In this reaction, bromide ions (Br-) are being replaced by iodine (I2). Since I- is a stronger reducing agent than Br-, the reaction is not favorable as Br- cannot be oxidized by I2. Therefore, this reaction **will not occur**.

### Step 4: Analyze the fourth reaction - Cu + H2
- **Reaction**: Cu + H2 → No reaction
- **Analysis**: Copper (Cu) is below hydrogen (H) in the electrochemical series, meaning it cannot displace hydrogen from any compound. Therefore, this reaction **will not occur**.

### Conclusion
From the analysis, the reaction that will not occur is **KBr + I2 → KI + Br2** due to the inability of bromide ions to be oxidized by iodine.

### Summary of Findings
- **Fe + H2SO4**: Occurs
- **Cu + AgNO3**: Occurs
- **KBr + I2**: Does not occur
- **Cu + H2**: Does not occur

### Final Answer
The reaction that will not occur is **KBr + I2 → KI + Br2**.

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