Colour of iodine solution is disappeared by shaking it with aqueous solution of

Options

A. `H_(2)SO_(4)`
B. `Na_(2)S`
C. `Na_(2)S_(2)O_(3)`
D. `Na_(2)SO_(4)`

Explanation

To solve the question regarding the disappearance of the color of iodine solution when shaken with an aqueous solution, we can follow these steps:

### Step 1: Understand the Nature of Iodine Solution
Iodine (I2) in solution typically has a brown color due to the presence of iodine molecules. This color can be affected by various chemical reactions.

**Hint:** Remember that iodine is a diatomic molecule and its color is a characteristic of its molecular form in solution.

### Step 2: Identify the Reactant
The question asks which aqueous solution can cause the color of iodine to disappear. One common reagent known for this purpose is sodium thiosulfate (Na2S2O3).

**Hint:** Consider common reducing agents that can react with iodine.

### Step 3: Write the Reaction
When iodine reacts with sodium thiosulfate, the following reaction occurs:
\[ \text{I}_2 + 2 \text{Na}_2\text{S}_2\text{O}_3 \rightarrow 2 \text{NaI} + \text{Na}_2\text{S}_4\text{O}_6 \]

In this reaction, iodine is reduced to iodide ions (NaI), which are colorless, thus causing the brown color of the iodine solution to disappear.

**Hint:** Look for a reaction where iodine is converted into a colorless species.

### Step 4: Analyze the Options
The options provided are:
1. H2SO4
2. Na2S
3. Na2S2O3
4. Na2SO4

From our understanding, sodium thiosulfate (Na2S2O3) is the correct choice as it effectively reduces iodine.

**Hint:** Cross-check the chemical formulas of the options with the known compounds.

### Step 5: Conclude the Answer
Based on the above analysis, the correct answer to the question is:
**Na2S2O3 (sodium thiosulfate)**.

**Final Answer:** The color of iodine solution disappears when shaken with an aqueous solution of sodium thiosulfate (Na2S2O3).